5 ms-1
Reason — Given,
u = 0; a = 0.5 ms-2 ; S = 25 m; v = ?
Using, v2 = u2 + 2aS
v2 = 0 + (2 × 0.5 × 25) = 25
Hence, v = 5 ms-1
Question
A body initially at rest, starts moving with a constant acceleration of 0.5 ms-2 and travels a distance 25 m, then its final velocity is: (i) 5 ms-1 (ii) 20 ms-1 (iii) 15 ms-1 (iv) -15 ms-1
- Motion in One Dimension ICSE
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