According to equation of motion
S = ut + 1/2 at2
distance covered = S
initial velocity u = 10 m s-1
acceleration a = 5 m s-2
time t = 5 s
Substituting the values in the formula, we get,
S = 10 × 5 + 1/2 × 5 × 5²
= 50 + 2.5 × 25
= 50 + 62.5 = 112.5 m
Hence, distance covered = 112.5 m.