R = 15 Ω
Potential difference = ?
From Ohm’s Law,
V = IR
Substituting the values in the formula, we get,
V = 0.2 × 15 = 3 V
Hence, the potential difference across the ends of the wire = 3 V
R = 15 Ω
Potential difference = ?
From Ohm’s Law,
V = IR
Substituting the values in the formula, we get,
V = 0.2 × 15 = 3 V
Hence, the potential difference across the ends of the wire = 3 V
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