Question

A hockey ball of mass 200 g travelling at 10 m s-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s-1 . Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

August 25, 2024

Answer

Mass of the hockey ball, m= 200 g = 0.2 kg

Hockey ball travels with velocity, v₁= 10 m/s

Initial momentum = mv₁

Hockey ball travels in the opposite direction with velocity, v₂= -5 m/s

Final momentum = mv₂

Change in momentum = mv₁– mv₂= 0.2 [10 – (-5)] = 0.2 (15) = 3 kg ms^-1

Hence, the change in momentum of the hockey ball is 3 kg ms^-1 .

Was this answer helpful?

Didn't liked the above answer ?

Text Generation Tool

💡 Some Related Questions

force and laws of motion

How much momentum will a dumbbell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 m s-2

force and laws of motion

Akhtar, Kiran and Rahul were riding in a motor car that was moving with a high velocity on an expressway when an insect hit the windshield and got stuck on the windscreen. Akhtar and Kiran started pondering over the situation. Kiran suggested that the insect suffered a greater change in momentum as compared to the change in momentum of the motorcar (because the change in the velocity of the insect was much more than that of the motorcar). Akhtar said that since the motorcar was moving with a larger velocity, it exerted a larger force on the insect. And as a result the insect died. Rahul while putting an entirely new explanation said that both the motorcar and the insect experienced the same force and a change in their momentum. Comment on these suggestions.

force and laws of motion

An object of mass 100 kg is accelerated uniformly from a velocity of 5 ms-1 to 8 ms-1 in 6 s. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object.

force and laws of motion

An object of mass 1 kg travelling in a straight line with a velocity of 10 ms-1 collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

force and laws of motion

A bullet of mass 10 g travelling horizontally with a velocity of 150 ms-1 strikes a stationary wooden block and comes to rest in 0.03 s. Calculate the distance of penetration of the bullet into the block. Also calculate the magnitude of the force exerted by the wooden block on the bullet.

force and laws of motion

Mass of one of the objects, m1 = 1.5 kg Mass of the other object, m2 = 1.5 kg Velocity of m1 before collision, v1 = 2.5 m/s Velocity of m2, moving in opposite direction before collision, v2 = -2.5 m/s (Negative sign arises because mass m2 is moving in an opposite direction) After collision, the two objects stick together. Total mass of the combined object = m1 + m2 Velocity of the combined object = v According to the law of conservation of momentum: Total momentum before collision = Total momentum after collision m1v1 + m2 v2 = (m1 + m2) v 1.5(2.5) + 1.5 (-2.5) = (1.5 + 1.5) v 3.75 – 3.75 = 3 v v = 0 Hence, the velocity of the combined object after collision is 0 m/s.

force and laws of motion

Two objects, each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 ms-1 before the collision during which they stick together. What will be the velocity of the combined object after collision?

force and laws of motion

Using a horizontal force of 200 N, we intend to move a wooden cabinet across a floor at a constant velocity. What is the friction force that will be exerted on the cabinet?

force and laws of motion

What is the momentum of an object of mass m, moving with a velocity v? (a) (mv) 2 (b) mv2 (c) ½mv2 (d) mv

force and laws of motion

An automobile vehicle has a mass of 1500 kg. What must be the force between the vehicle and road if the vehicle is to be stopped with a negative acceleration of 1.7 ms-2 ?

error: Content is protected !! 💀