Required least force = 10N
r = 25cm = 0.25 m
We know the moment of force = F × r
Substituting the values of F and r we get,
Moment of force = 10 × 0.25 = 2.5 Nm
Hence, moment of force needed to turn the nut = 2.5 Nm
Calculate the moment of force about (i) the centre O, and (ii) the point A.
Question
A nut is opened by a wrench of length 25 cm. If the least force required is 10 N, find the moment of force needed to turn the nut.
- Category: Force Class 10 ICSE
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