Question

A piece of stone of mass 113 g sinks to the bottom in water contained in a measuring cylinder and water level in cylinder rises from 30 ml to 40 ml. Calculate R.D. of stone.

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Answer

Mass of stone = 113 g

The rise in the level of water is equivalent to the volume occupied by the stone

Rise in water level = 40 ml – 30 ml = 10 ml

∴ The volume occupied by the stone = 10 cm3

Density = Mass\over Volume

= 113\over 10 = 11.3 g cm-3

Therefore, density of stone = 11.3 g cm-3

RD of stone = 11.3\over 1 = 11.3

Relative density of stone = 11.3

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