Mass of the body (m) = 20 kg
Initial velocity (u) = 5 m/s
Final velocity (v) = 2 m/s
We know that,
Work done (W) = Change in kinetic Energy
={1\over2}mu2 −{1\over2}mv2
={1\over2}m(u2 − v2 )
={1\over2}(20)(52 − 22 )
= 10(25 − 4)
= 210 J
Question
Certain force acting on a 20 kg mass changes its velocity from 5 m s–1 to 2 m s–1 . Calculate the work done by the force.
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