Mass of the body = 20 kg
Initial velocity = 5 m/s
Final velocity = 2 m/s
We know that,
𝑊𝑜𝑟𝑘 𝑑𝑜𝑛𝑒 = 𝑐ℎ𝑎𝑛𝑔𝑒 𝑖𝑛 𝑘𝑖𝑛𝑒𝑡𝑖𝑐 𝑒𝑛𝑒𝑟𝑔𝑦
={1\over2}𝑚𝑢2 −{1\over2}𝑚𝑣2
={1\over2}𝑚(𝑢2 − 𝑣2 )
={1\over2}(20)(52 − 22 )
= 10(25 − 4)
= 210 J
Question
Certain force acting on a 20 kg mass changes its velocity from 5 m s–1 to 2 m s–1 . Calculate the work done by the force.
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