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Explain with the help of : (i) an ionic equation (ii) electron dot structural diagram the formation of the following :
(a) Sodium chloride
(b) Calcium oxide
(c) Magnesium chloride.
(at. nos. Na = 11, Cl = 17, Ca = 20, O = 8, Mg = 12)

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Answer

(a) Sodium Chloride :

Ionic equation

Na – 1e ⟶ Na1+ [oxidation]
[atom]      [cation]
[2,8,1]       [2,8]

Cl + 1e ⟶ Cl1- [reduction]
[atom]      [anion]
[2,8,7]       [2,8,8]

Na + Cl ⟶ Na1+ Cl1- ⟶ NaCl

Electron dot structural diagram

sodium-chloride-electron-dot-diagram-simplified-chemistry-icse-class-10-600x210

(b) Calcium Oxide

Ionic Equation

Ca – 2e ⟶ Ca2+ [oxidation]
[atom]      [cation]
[2,8,8,2]     [2,8,8]

O + 2e ⟶ O2- [reduction]
[atom]      [anion]
[2,6]          [2,8]

Ca + O ⟶ Ca2+O2- ⟶ CaO

Electron dot structural diagram

calcium-oxide-electron-dot-diagram-simplified-chemistry-icse-class-10-911x316

(c) Magnesium chloride.

Ionic Equation

Mg – 2e ⟶ Mg2+ [oxidation]
[atom]      [cation]
[2,8,2]       [2,8]

2Cl + 2e ⟶ 2Cl [reduction]
[atom]      [anion]
[2,8,7]       [2,8,8]

Mg + 2Cl ⟶ Mg2+2Cl ⟶ MgCl2

Electron dot structural diagram

magnesium chloride electron dot diagram simplified chemistry icse class 10 1097x534 2

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