The nature of the graph shows that velocity changes by equal amounts in equal intervals of time. For a uniformly accelerated motion, velocity-time graph is always a straight line.
As we know, acceleration is equal to the slope of the graph
i.e., a = BC \over AC or a = v_2 - v_1 \over t_2 - t_1
∴ a = (10.0 - 7.5)ms^{-1} \over (20 - 15)s
Or a = 2.5 ms^{-1} \over 5s
Or a = 0.5 ms-2
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| Time in (s) | Body (A) | Body (B) | Body (C) |
| 1stSecond | 20 | 20 | 20 |
| 2ndSecond | 20 | 36 | 60 |
| 3rdSecond | 20 | 24 | 100 |
| 4thSecond | 20 | 30 | 140 |
| 5thSecond | 20 | 48 | 180 |
Observe the graph carefully and answer the following questions. (i) Which part of the graph shows the squirrel moving away from the tree? (ii) Name the point on the graph which is 6 m away from the base of the tree. (ii) Which part of the graph shows that the squirrel is not moving? (iv) Which part of the graph shows that the squirrel is returning to the tree? (v) Calculate the speed of the squirrel from the graph during its journey.
