Density of ice = 0.9 g cm-3
Density of sea water = 1.1 g cm-3
By the principle of floatation,
{Volume\ of\ immersed\ part\over Total\ volume} = {Density\ of\ ice\over Density\ of\ sea\ water}∴ {Volume\ of\ immersed\ part\over Total\ volume} = {0.9\over 1.1}= {9\over 11}= 0.818
Hence, the volume of icebergs that will remain below the surface of water in the sea = {9\over 11} th of total volume (or 0.818th) part.