Question
Calculate the percentage of composition of the constituents of calcium carbonate. [Ca = 40, C = 12, O = 16]
Answer
The molecular weight of CaCO3 = 40+12+16×3 = 100 g
We know, % Composition = {mass\ of\ element\over moleclar\ mass}×100
% Composition of Ca = {40\over 100}×100 = 40
% Composition of C = {12\over 100}×100 = 12
% Composition of Oxygen = {48\over 100}×100 = 48
