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LAQ : Calculate the percentage of composition of the constituents of calcium carbonate

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Calculate the percentage of composition of the constituents of calcium carbonate. [Ca = 40, C = 12, O = 16]

Answer

The molecular weight of CaCO3 = 40+12+16×3 = 100 g

We know, % Composition = {mass\ of\ element\over moleclar\ mass}×100

% Composition of Ca = {40\over 100}×100 = 40

% Composition of C = {12\over 100}×100 = 12

% Composition of Oxygen = {48\over 100}×100 = 48

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