Question

LAQ : How many litres of oxygen is needed to burn completely 2.2 g propone (C3H8)?

Answer

WhatsApp

Question

How many litres of oxygen is needed to burn completely 2.2 g propone (C3H8)?

Answer

Balanced chemical equation:

C3H8 + 5O2 = 3CO2 + 4H2O

Molecular Mass of C3H8 = 12 × 3 + 1 × 8 = 44 g

Volume of 5O2 = 5 × 22.4 = 112 L

Clearly, 44 g of propane burns completely in 112 L of oxygen

∴ To burn 2.2g of propane completely, the amount of oxygen needed is (112×2.2)/44 = 5.6 L

Was this answer helpful?

Didn't liked the above answer ?

Subscribe
Notify of

Related Questions