Using the equation of motion s = ut + {1 \over2}at^2
Distance travelled in 5 seconds, s = u \times 5 + {1\over2}a \times 5^2
Or s = 5u+{25\over2}a …….(1)
Similarly, distance travelled in 4 seconds, s’ = 4u+{16\over2}a ….(2)
Distance travelled in the interval between 4th and 5th seconds
= (s – s’) = (u+{9\over2}a)m
Observe the graph carefully and answer the following questions. (i) Which part of the graph shows the squirrel moving away from the tree? (ii) Name the point on the graph which is 6 m away from the base of the tree. (ii) Which part of the graph shows that the squirrel is not moving? (iv) Which part of the graph shows that the squirrel is returning to the tree? (v) Calculate the speed of the squirrel from the graph during its journey.