The density of ice is 0.92 g cm^-3 and that of sea water is 1.025 g cm^-3. Find the total volume of an iceberg which floats with it’s volume 800 cm³ above water.

Given,

Density of ice = 0.92 g cm^-3

Density of sea water = 1.025 g cm^-3

Let the total volume of the iceberg be V cm³

The volume of the iceberg above sea water = 800 cm³

Volume of iceberg immersed in seawater = (V – 800) cm³

By the principle of floatation,

⇒ {V-800\over V} = {0.92\over 1.025}

⇒ 1.025 V – 820 = 0.92 V

⇒ 1.025 V – 0.92 V = 820

⇒ 0.105 V = 820

⇒ V = 820\over 0.105 = 7809.52 cm³

Hence, Total volume of iceberg = 7809.52 cm³