Question
The velocity-time graph of the motion of a car is given. Find the distance travelled by the car in the first six seconds. What is the retardation of the car during the last two seconds? [Ans. 90 m, 15 m/s2]
Solution
(a) Distance travelled in 6 s = Area under the graph from 0 to 6 s
= Area under the graph from 0 to 2 s + Area under the graph from 2 to 6 s
= 1\over 2 × 2 × 30 + (6 – 2) × 30
= 1\over 2 × 2 × 30 + 4 × 30
= 30 + 120 = 150 m
(b) Retardation (a) = (u - v)\over t
= (30 - 0)\over 2
= 30\over 2
= 15 m/s2