Question

The velocity-time graph of the motion of a car is given. Find the distance travelled by the car in the first six seconds

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Answer

Question

The velocity-time graph of the motion of a car is given. Find the distance travelled by the car in the first six seconds. What is the retardation of the car during the last two seconds? [Ans. 90 m, 15 m/s2]

Selina Class 7 Chemistry 9

Solution

(a) Distance travelled in 6 s = Area under the graph from 0 to 6 s

= Area under the graph from 0 to 2 s + Area under the graph from 2 to 6 s

= 1\over 2 × 2 × 30 + (6 – 2) × 30

= 1\over 2 × 2 × 30 + 4 × 30

= 30 + 120 = 150 m

(b) Retardation (a) = (u - v)\over t

= (30 - 0)\over 2

= 30\over 2

= 15 m/s2

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