**There are two cases possible:**

Case 1 — If angle θ° between the mirrors is such that

n = 360\over θ

- the number of images is n, when the object is placed asymmetrically between the mirrors.
- the number of images is n – 1, when the object is placed symmetrically (i.e., on the bisector of the angle) between the mirrors.

Case 2 — If n = 360\over θ is even, the number of images is always n – 1 for all positions of object in between the mirrors.