QQuestion
A fixed mass of gas kept at 0°C is heated. What will be the temperature of the gas when both its pressure and volume are doubled compared to the initial values?
✓Answer
Initial temperature (T₁) = 0°C = 273 K
Let initial pressure = P₁ and initial volume = V₁
Final pressure (P₂) = 2P₁
Final volume (V₂) = 2V₁
From Combined Gas Law: \frac{\text{P₁V₁}}{\text{T₁}}=\frac{\text{P₂V₂}}{\text{T₂}}
⇒ \frac{\text{P₁V₁}}{273}=\frac{2\text{P₁}\times2\text{V₁}}{\text{T₂}}
⇒ T₂ = 4 × 273 = 1092 K
⇒ T₂ = 1092 − 273 = 819°C
Hence, the final temperature of the gas is 819°C.
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