QQuestion
The mass of 11.2 L of NH₃ gas at S.T.P. is:
[N = 14, H = 1]
(a) 17 g
(b) 8.5 g
(c) 34 g
(d) 11.2 g
✓Answer
(b) 8.5 g
Explanation
At S.T.P., 1 mole of any gas occupies 22.4 L.
Therefore, 11.2 L of NH₃ = \frac{11.2}{22.4} = 0.5 mol
Molar mass of NH₃ = 14 + (1 × 3) = 17 g/mol
Mass of 0.5 mol NH₃ = 0.5 × 17 = 8.5 g
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