Skip to content
ICSEClass 10MathematicsMeasures Of Central Tendency06 Mark2026 Easy

QQuestion

Using a graph paper, draw an ogive for the following distribution which shows a record of weight in kilograms of 100 students.

Weight (in kg) Number of students
35–40 4
40–45 6
45–50 10
50–55 24
55–60 26
60–65 17
65–70 8
70–75 5

Use your ogive to estimate the following:

(a) the median weight of the students.

(b) percentage of students whose weight is 60 kg or more.

(c) the weight above which 20% of the students lie.

Exam-ready answer • 06 Mark

Answer

The cumulative-frequency table for the given continuous distribution is:

Weight (in kg) Number of students Cumulative frequency
35–40 4 4
40–45 6 10
45–50 10 20
50–55 24 44
55–60 26 70
60–65 17 87
65–70 8 95
70–75 5 100

Using a graph paper, draw an ogive for the following distribution which shows a record of weight in kilograms of 100 students

(a) Total number of students, N = 100

Median position = \frac{\mathrm{N}}{2} = \frac{100}{2} = 50

From the ogive, the median weight is approximately 56 kg.

(b) Cumulative frequency at 60 kg = 70

Number of students weighing 60 kg or more = 100 − 70 = 30

Percentage = \frac{30}{100}\times100 = 30%

Therefore, 30% of the students weigh 60 kg or more.

(c) Number of students above the required weight = 20% of 100 = 20

Therefore, the cumulative frequency below the required weight = 100 − 20 = 80.

From the ogive, the weight corresponding to cumulative frequency 80 is approximately 63 kg.

Therefore, the weight above which 20% of the students lie is approximately 63 kg.

Was this answer helpful?

Related Questions

More ICSE Easy level questions

1/12

Rakhi’s mobile number has the following integers : 1, 6, 9, 8, 9, 1, 7, 8, 9 The mode of the above given data is : (a) 1 (b) 6 (c) 8 (d) 9

Easy 01 Mark

Find the mean of the following frequency distribution using step-deviation method. Take assumed mean = 28. Class interval Frequency 0–8 10 8–16 20 16–24 14 24–32 16 32–40 18 40–48 22

Easy 03 Mark

Use graph paper to answer this question. During a medical check-up of 60 students in a school, their weights were recorded as follows: Weight (kg) Number of students 28–30 2 30–32 4 32–34 10 34–36 13 36–38 15 38–40 9 40–42 5 42–44 2 Taking 2 cm = 2 kg along one axis and 2 cm = 10 students along the other axis, draw an ogive. Use the graph to find: (a) the median (b) the upper quartile (c) the number of students whose weight is above 37 kg.

Easy 06 Mark

The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution using the shortcut method. Marks Number of students (f) 0–10 3 10–20 8 20–30 14 30–40 9 40–50 4 50–60 2

Easy 03 Mark

The following distribution gives the daily wages of 60 workers of a factory: Daily income (₹) Number of workers 200–300 6 300–400 10 400–500 14 500–600 16 600–700 10 700–800 4 Use graph paper. Take 2 cm = ₹100 along one axis and 2 cm = 2 workers along the other axis. Draw a histogram and hence find the mode of the distribution.

Easy 03 Mark

The following observations are arranged in ascending order: 27, 31, 46, 52, x, x + 4, 71, 79, 85, 90 If the median is 64, then the value of x is: (a) 60 (b) 61 (c) 62 (d) 66

Easy 01 Mark

Which of the following cannot be determined graphically for a grouped frequency distribution? (a) Median (b) Mode (c) Quartiles (d) Mean

Easy 01 Mark

Assertion (A): The mean of the first 9 natural numbers is 4.5. Reason (R): Mean = (a) A is true, R is false. (b) A is false, R is true. (c) Both A and R are true, and R is the correct reason for A. (d) Both A and R are true, and R is not the correct reason for A.

Easy 01 Mark

The histogram drawn on the graph represents the number of students of different heights (in cm). Using the graph, answer the following: (a) the number of students whose height is 150 cm and above. (b) the modal height. (c) the total number of students.

Moderate 03 Mark

A life insurance agent found the following distribution of ages of 100 policy holders: Age (years) Frequency Cumulative frequency 20–25 2 2 25–30 4 6 30–35 12 18 35–40 20 38 40–45 28 66 45–50 22 88 50–55 8 96 55–60 4 100 On a graph sheet, draw an ogive using the given data. Take 2 cm = 5 years along one axis and 2 cm = 10 policy holders along the other axis. Use your graph to find: (a) the median age. (b) the number of policy holders whose age is above 52 years.

Moderate 04 Mark

The given graph represents the monthly salaries, in rupees, of workers of a factory. Using the graph, find: (a) the total number of workers. (b) the median class. (c) the lower-quartile class. (d) the number of workers with monthly salary greater than or equal to ₹6,000 but less than ₹10,000.

Moderate 04 Mark

For the following frequency distribution, find: (a) the mean, to the nearest whole number. (b) the median. x 10 11 12 13 14 15 16 f 3 2 2 6 3 5 3

Moderate 03 Mark