Mass of N₂ = 14 g

Molar mass of N₂ = 28 g/mol

Pressure (P) = 83.14 cm Hg = 1.094 atm

Temperature (T) = 227°C = 500 K

Gas Constant (R) = 0.082 L atm mol⁻¹ K⁻¹

Volume (V) = ?

Number of moles = \frac{\text{Mass}}{\text{Molar Mass}}

= \frac{14}{28}

= 0.5 mol

Using the Ideal Gas Equation, PV = nRT

Volume (V) = \frac{nRT}{P}

= \frac{0.5\times0.082\times500}{1.094}

≈ 18.74 L

≈ 19 L

Hence, the volume of 14 g of nitrogen gas is approximately 19 L.