QQuestion
Find the volume of 14 g Nitrogen gas at a temperature of 227°C and at pressure of 83.14 cm of Hg.
[R = 8.314 J mol⁻¹ K⁻¹]
✓Answer
Mass of N₂ = 14 g
Molar mass of N₂ = 28 g/mol
Pressure (P) = 83.14 cm Hg = 1.094 atm
Temperature (T) = 227°C = 500 K
Gas Constant (R) = 0.082 L atm mol⁻¹ K⁻¹
Volume (V) = ?
Number of moles = \frac{\text{Mass}}{\text{Molar Mass}}
= \frac{14}{28}
= 0.5 mol
Using the Ideal Gas Equation, PV = nRT
Volume (V) = \frac{nRT}{P}
= \frac{0.5\times0.082\times500}{1.094}
≈ 18.74 L
≈ 19 L
Hence, the volume of 14 g of nitrogen gas is approximately 19 L.
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