QQuestion
The equation of the line passing through the origin and parallel to the line 3x + 4y + 7 = 0 is:
(a) 3x + 4y + 5 = 0
(b) 4x − 3y − 5 = 0
(c) 4x − 3y = 0
(d) 3x + 4y = 0
The equation of the line passing through the origin and parallel to the line 3x + 4y + 7 = 0 is:
(a) 3x + 4y + 5 = 0
(b) 4x − 3y − 5 = 0
(c) 4x − 3y = 0
(d) 3x + 4y = 0
(d) 3x + 4y = 0
Explanation:
Parallel lines have the same coefficients of x and y.
A line parallel to 3x + 4y + 7 = 0 has the form:
3x + 4y + c = 0
It passes through the origin (0, 0).
Substituting x = 0 and y = 0:
3(0) + 4(0) + c = 0
⇒ c = 0
Therefore, the required equation is 3x + 4y = 0.
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