QQuestion
In the given diagram, △ABC ∼ △EFG. If ∠ABC = ∠EFG = 60°, then the length of side FG is:

(a) 15 cm
(b) 20 cm
(c) 25 cm
(d) 30 cm
In the given diagram, △ABC ∼ △EFG. If ∠ABC = ∠EFG = 60°, then the length of side FG is:

(a) 15 cm
(b) 20 cm
(c) 25 cm
(d) 30 cm
(a) 15 cm
Explanation:
Given, △ABC ∼ △EFG.
Therefore, corresponding sides are proportional.
\frac{AB}{EF}=\frac{BC}{FG}From the diagram, AB = 15 cm, EF = 75 cm and BC = 3 cm.
\frac{15}{75}=\frac{3}{FG}⇒ \frac{1}{5}=\frac{3}{FG}
⇒ FG = 3 × 5
⇒ FG = 15 cm
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