QQuestion
If 0° < θ < 90° then sin θ < sin²θ
✓Answer
False
Explanation:
We know that for 0° < θ < 90°,
0 < sin θ < 1
Since squaring a fraction between 0 and 1 makes it smaller, we get:
sin² θ < sin θ
But the given statement claims sin θ < sin²θ, which is incorrect.
Related Questions
More WBBSE Moderate level questions
Find x, if sin x = cos (x – 20°)
If tan θ cos 60° = then the value of sin(θ - 15°) is _____.
If r cosθ = 2√3 and r sinθ = 2, then find the value of r and θ when 0° < θ < 90°.
If tan 2A = cot(A – 30°), then find the value of sec(A + 20°)
If sin (θ + 30°) = cos 15°, then find the value of cos 2θ.
State True or False: The values of cos 36° and sin 54° are equal.
If ∠A and ∠B are complementary then ∠A + ∠B = _____
If sin 17° = then show that sec 17° - sin 73° =
If tan θ = find the value of sin θ.
Find the ratio of length of radius and perimeter of a circle
If the roots of a quadratic equation ax² + bx + c = 0 (a ≠ 0) are reciprocal and opposite in sign. Find (a + c)
In a joint business one of the two friends invests ₹ xyz for y months and the other ₹ y²z for x months. At the end of the agreements, the profit would be distributed in the ratio x : y.