QQuestion
Solve: \frac{x-3}{x+3} – \frac{x+3}{x-3} + 6 \frac{6}{7} = 0
✓Answer
\text{x² - 6x + 9 - (x² + 6x + 9)}\over x² - 9 + 48\over 7 = 0
or, – \text{12x}\over \text{x² - 9} + 48\over 7 = 0
or, -84x + 48x² – 432 = 0
or, -7x + 4x² – 36 = 0
or, 4x² – 7x – 36 = 0
or, 4x² – (16x – 9x) – 36 = 0
or, 4x² – 16x + 9x – 36 = 0
or, 4x(x – 4) + 9(x – 4) = 0
or, (x – 4)(4x + 9) = 0
x = 4, -9/4
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