The electronic configuration of Na and Cl atoms in the compound NaCl is
(a) Na – 2, 8, 8 : Cl – 2, 8
(b) Na – 2, 8, 7 : Cl – 2, 8, 1
(c) Na – 2, 8, 1 : Cl – 2, 8, 7
(d) Na – 2, 8, : Cl – 2, 8, 8
WBBSE
Class X
Physical Science
Ionic and Covalent Bond
01 Mark
2024
(c) Na – 2, 8, 1 : Cl – 2, 8, 7
Explanation
Sodium (Na) has an electron configuration of 2, 8, 1, and chlorine (Cl) has an electron configuration of 2, 8, 7. In NaCl, Na loses one electron and Cl gains one electron to form a stable ionic bond.
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