LAQ : How many grams of calcium carbonate will be needed for the preparation of 22 gm of carbon dioxide by reaction with dilute hydrochloric acid and calcium carbonate?

Question

How many grams of calcium carbonate will be needed for the preparation of 22 gm of carbon dioxide by reaction with dilute hydrochloric acid and calcium carbonate?

[Ca = 40, C = 12, 0 =16]

Answer

Balanced Chemical Equation:

CaCO₃ + 2HCl = CaCl₂ + CO₂ + H₂O

The molecular weight of CaCO₃ = 40 + 12 + 48 = 100 g

The molecular weight of CO₂ = 44 g

It is seen from the equation that to produce 44 g of CO₂, 100 g of CaCO₃ is necessary.

Hence, to produce 22 of CO₂, CaCO₃ is necessary

= 100×22\over 44 = 50 g