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For a floating body of volume V, the relation between the volume of its submerged part v, the densities of liquid (ρL) and the body (ρS) is :
(a) v/V = ρsL
(b) V/v= ρsL
(c) v × ρs = V × ρL
(d) none of these

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A weather forecasting plastic balloon of volume 15 m3 contains hydrogen of density 0.09 kg m-3. The volume of an equipment carried by the balloon is negligible compared to it’s own volume. The mass of the empty balloon alone is 7.15 kg. The balloon is floating in air of density 1.3 kg m-3. Calculate : (i) the mass of hydrogen in the balloon, (ii) the mass of hydrogen and balloon, (iii) the total mass of hydrogen, balloon and equipment if the mass of equipment is x kg, (iv) the mass of air displaced by balloon and (v) the mass of equipment using the law of floatation.

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