QQuestion
Study the reaction scheme shown below and identify the reactants A, B and C.
ICSEClass 10ChemistryOrganic Chemistry03 Mark2026 Moderate
✓Answer
A → Concentrated Sulphuric Acid (conc. H2SO4)
B → Acetic acid (CH3COOH)
C → Oxygen (O2)
Explanation –
Ethanol ⟶ Ethene (with reactant A): This is dehydration of ethanol. A is concentrated sulphuric acid (conc. H2SO4) at 170°C.
\mathrm{C_2H_5OH} \xrightarrow[\;170^\circ\mathrm{C}\;]{\mathrm{Conc.\ H_2SO_4}} \mathrm{C_2H_4} + \mathrm{H_2O}Ethanol ⟶ Ethyl acetate (with reactant B): This is esterification. B is acetic acid (CH3COOH) in the presence of conc. H2SO4 (acts as a catalyst).
\mathrm{C_2H_5OH} + \mathrm{CH_3COOH} \xrightarrow{\mathrm{Conc.\ H_2SO_4}} \mathrm{CH_3COOC_2H_5} + \mathrm{H_2O}Ethanol ⟶ Carbon dioxide + Water (with reactant C): This is combustion. C is oxygen (O2).
C2H5OH + 3O2 ⟶ 2CO2 + 3H2O
Hence, A = Concentrated H2SO4, B = Acetic acid (CH3COOH), and C = Oxygen (O2).
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