ICSEClass XPhysicsForce03 Mark2025 Easy

QQuestion

Akash takes a uniform metre scale and suspends a weight of 2 N at one end ‘X’, and a weight of 5 N on the other end ‘Y’. He then balances the ruler horizontally on a knife edge placed at 70 cm from X. Draw a diagram of the arrangement and calculate the weight of the ruler.

Exam-ready answer 03 Mark

Answer

The diagram of the arrangement is shown below.

Akash takes a uniform metre scale and suspends a weight of 2 N at one end

Given,

Weight at end X = 2 N

Weight at end Y = 5 N

Distance of X from the knife edge = 70 cm

Distance of Y from the knife edge = 100 − 70 = 30 cm

Let the weight of the scale be W. Its weight acts at the 50 cm mark, 20 cm from the knife edge.

For equilibrium,

Anticlockwise moment = Clockwise moment

2 × 70 + W × 20 = 5 × 30

140 + 20W = 150

20W = 10

W = 0.5 N

Therefore, the weight of the ruler is 0.5 N.

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