QQuestion
ABC is a triangle whose vertices are A(1, −1), B(0, 4) and C(−6, 4). D is the midpoint of BC. Find:
(a) the coordinates of D
(b) the equation of the median AD.
Exam-ready answer • 03 Mark
✓Answer
(a) D is the midpoint of B(0, 4) and C(−6, 4).

Using the midpoint formula:
D = \left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\right)
D = \left(\frac{0+(-6)}{2},\frac{4+4}{2}\right)
D = \left(\frac{-6}{2},\frac{8}{2}\right)
Therefore, D = (−3, 4).
(b) The median AD passes through A(1, −1) and D(−3, 4).
⇒ y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)
⇒ y-(-1)=\frac{4-(-1)}{-3-1}(x-1)
⇒ y+1=\frac{5}{-4}(x-1)
⇒ −4(y + 1) = 5(x − 1)
⇒ −4y − 4 = 5x − 5
⇒ 5x + 4y = 1
Therefore, the equation of median AD is 5x + 4y = 1.
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