Question

A body of mass 3.5 kg displaces 1000 cm3 of water when fully immersed inside it. Calculate (i) the volume of body, (ii) the upthrust on body and (iii) the apparent weight of body in water.

WhatsApp

Answer

Mass = 3.5 kg

Therefore, weight = 3.5 kgf

Volume of displaced water = 1000 cm3

(i) Volume of body = volume of the water displaced = 1000 cm3

Hence, the volume of body = 1000 cm3

(ii) Upthrust on body = volume of the body × density of water × g

= 1000 × 0.001 × g = 1 kgf

(iii) The apparent weight of body in water = true weight – upthrust

= 3.5 – 1

= 2.5 kgf

Was this answer helpful?

Didn't liked the above answer ?

Text Generation Tool

💡 Some Related Questions

Upthrust in Fluids

A weather forecasting plastic balloon of volume 15 m3 contains hydrogen of density 0.09 kg m-3. The volume of an equipment carried by the balloon is negligible compared to it’s own volume. The mass of the empty balloon alone is 7.15 kg. The balloon is floating in air of density 1.3 kg m-3. Calculate : (i) the mass of hydrogen in the balloon, (ii) the mass of hydrogen and balloon, (iii) the total mass of hydrogen, balloon and equipment if the mass of equipment is x kg, (iv) the mass of air displaced by balloon and (v) the mass of equipment using the law of floatation.

Open Answer »