Weight of the solid in air (W1) = 44.5 gf
Density of the iron = 8.9 x 103 kg m-3
RD of iron = 8.9 × 1000\over 1000
= 8.9
RD = W_1\over W_1 - W_2
⇒ 8.9 = 44.5\over 44.5 - W_2
⇒ 8.9 (44.5 – W2) = 44.5
⇒ 396.05 – 8.9 W2 = 44.5
⇒ 8.9 W2 = 396.05 – 44.5
⇒ W2 = 351.55\over 8.9 = 39.5 gm
Hence,
Weight of iron piece when immersed in water = 39.5 gm