Question

A silver ornament of mass ‘m’ gram is polished with gold equivalent to 1% of the mass of silver. Compute the ratio of the number of atoms of gold and silver in the ornament.

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Answer

Mass of silver = m g

Mass of gold = 𝑚/100 g

Number of atoms of silver = Mass/Atomic mass × NA

= 𝑚 / 108 × NA

Number of atoms of gold = Mass/Atomic mass × NA

= (𝑚 / 100 × 197) × NA

Ratio of number of atoms of gold to silver = Au : Ag

= (𝑚/100 × 197 )× NA : (𝑚/108) × NA

= 100 x 197 : 108

= 19700 108

                                          = 182.41 : 1

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