5.85 g of NaCl = 5.85 / 58.5 = 0.1 moles
or 0.1 moles of NaCl particle.
Each NaCl particle is equivalent to 2 ions, i.e., one Na+ and one Cl–
⇒ Total moles of ions = 0.1 × 2 = 0.2 moles
Number of ions = 0.2 × 6.022 × 1023
= 1.2042 x 1023 ions
Question
Compute the number of ions present in 5.85 g of sodium chloride.
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Open Answer »A colorless liquid is thought to be a pure compound. Analysis of three samples of the material yield the following results.
| Mass of Sample | Mass of carbon | Mass of Hydrogen | |
| Sample 1 | 1.0 g | 0.862 g | 0.138 g |
| Sample 2 | 1.549 g | 1.335 g | 0.214 g |
| Sample 3 | 0.988 g | 0.852 g | 0.136 g |