Question
How many moles of potassium chlorate are required to produce 4.8 gm of oxygen?
Answer
Balanced chemical equation:
2KClO3 = 2KCl + 3O2
2 moles 3 moles
32 gm of oxygen = 1 mole
∴ 4.8 gm of oxygen = 1×4.8\over32 = 0.15 mole
It is seen from the equation that 3 moles of oxygen are produced from 2 moles of potassium chlorate.
∴ 0.15 moles of oxygen is produced from 2×0.15\over3 = 0.10 moles of potassium chlorate.
