Question
How much NH4Cl is needed to prepare 10 litres of ammonia at STP?
Answer
Balanced chemical equation:
NH4Cl = NH3 + HCl
Molecular Mass of NH4Cl = 53.5 g
The volume of NH3 = 22.4 L
Clearly, 22.4 L of ammonia is produced from 53.5 g of ammonium chloride.
∴ 10 L of ammonia can be produced from (53.5×10)/22.4 = 23.884 g of ammonium chloride.