LAQ : How much NH4Cl is needed to prepare 10 litres of ammonia at STP?

Question

How much NH₄Cl is needed to prepare 10 litres of ammonia at STP?

Answer

Balanced chemical equation:

NH₄Cl = NH₃ + HCl

Molecular Mass of NH₄Cl = 53.5 g

The volume of NH₃ = 22.4 L

Clearly, 22.4 L of ammonia is produced from 53.5 g of ammonium chloride.

∴ 10 L of ammonia can be produced from (53.5×10)/22.4 = 23.884 g of ammonium chloride.