Question

LAQ : How much NH4Cl is needed to prepare 10 litres of ammonia at STP?

  • Chemical Calculations
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Answer

Question

How much NH4Cl is needed to prepare 10 litres of ammonia at STP?

Answer

Balanced chemical equation:

NH4Cl = NH3 + HCl

Molecular Mass of NH4Cl = 53.5 g

The volume of NH3 = 22.4 L

Clearly, 22.4 L of ammonia is produced from 53.5 g of ammonium chloride.

∴ 10 L of ammonia can be produced from (53.5×10)/22.4 = 23.884 g of ammonium chloride.

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