MCQ : The number of atoms present in 3.7 g of nitrogen is

Question

The number of atoms present in 3.7 g of nitrogen is

1. 4.45 × 10²⁴
2. 6.023 × 10²⁴
3. 1.59 × 10²³
4. 3.023 × 10²³

Answer

(c) 1.59 × 10²³

Explanation

Number of moles of nitrogen

= 3.7 \over 14

= 0.264 mol

Number of atoms of nitrogen

= 0.264 mol × 6.022 × 10²³

= 1.59 × 10²³ atoms