Question
The volume of CO2 Produced at STP from 1 mole of calcium carbonate is
- 22.4 L
- 11.2 L
- 5.6 L
- 11 L
Answer
(a) 22.4 L
Explanation:
CaCO3(s) → CaO(s) + CO2(g)
From this equation, you can see that 1 mole of calcium carbonate produces 1 mole of carbon dioxide gas. At STP, 1 mole of any ideal gas occupies 22.4 liters. Therefore, 1 mole of CO2 gas produced from 1 mole of calcium carbonate at STP will occupy 22.4 liters.
So, the correct answer is 22.4 liters.