At STP what is the volume of 7 g of nitrogen gas? [Ans. 5.6 L]
Step 1: Calculation of number of moles
moles of N2 = mass\ of\ N_2 \over molar\ mass\ of\ N_2
= 7 \over 28 = 0.25 mol
Step 2: Calculation of Volume
At STP, one mole of any ideal gas occupies 22.4 L. Therefore, the volume of 0.25 mol of nitrogen gas is:
volume of N2 = 0.25 × 22.4 = 5.6 L
Therefore, the volume of 7 g of nitrogen gas at STP is 5.6 L.