SO3 is prepared by oxidizing SO2 with oxygen. How many grams of SO2 will be required to produce 40 g of SO3 ? [O = 16, S = 32] [Ans. 32 g]
The balanced chemical equation for the reaction of SO2 with O2 to form SO3 is:
2 SO2 + O2 → 2 SO3
Molar mass of SO3 = 1 × 32 + 3 × 16 = 80
Number of moles of SO3 = 40\over 80 = 0.5 mol
Since the molar ratio of SO2 to SO3 is 1:1, we need the same number of moles of SO2 as SO3 to react completely. Therefore, the number of moles of SO2 required is also 0.5 mol.
Finally, we can use the molar mass of SO2 to calculate the mass of SO2 required:
Mass of SO2 = 0.5 × 64 = 32 g
Therefore, 32 g of SO2 will be required to produce 40 g of SO3.