**Question**

**What is the volume of 11 g of CO _{2} at STP? [Ans. 5.6 L] **

**Answer**

Given mass = 11 g

Molar mass = 12 + 16 × 2 = 44

**Step 1: Calculation of number of moles**

Moles of CO_{2} = Given\ mass \over Molar\ mass

= 11 \over 44 = 0.25 mol

**Step 2: Calculation of number of moles**

volume of CO_{2} = number of moles of CO2 × molar volume at STP

= 0.25 × 22.4 = 5.6 L

Therefore, the volume of 11 g of CO2 at STP is 5.6 L.