Question
What is the volume of 11 g of CO2 at STP? [Ans. 5.6 L]
Answer
Given mass = 11 g
Molar mass = 12 + 16 × 2 = 44
Step 1: Calculation of number of moles
Moles of CO2 = Given\ mass \over Molar\ mass
= 11 \over 44 = 0.25 mol
Step 2: Calculation of number of moles
volume of CO2 = number of moles of CO2 × molar volume at STP
= 0.25 × 22.4 = 5.6 L
Therefore, the volume of 11 g of CO2 at STP is 5.6 L.
