**Question**

**What is the volume of 32 g of gas (having a molar mass of 64), at STP? [Ans. 11.2 L]**

**Answer**

**Step 1: Calculation of Number of moles**

Number of moles = mass \over molar\ mass

= 32 \over 64 = 0.5 mol

**Step 2: Calculation of volume**

At STP, the molar volume of an ideal gas is 22.4 L/mol.

Therefore, the volume of 0.5 mol of the gas at STP is:

volume = moles × molar volume

= 0.5 × 22.4 = 11.2 L