Flash Education

Question

You are provided with a hollow iron ball A of volume 15 cm3 and mass 12 g and a solid iron ball B of mass 12 g. Both are placed on the surface of water contained in a large tub. (a) Find upthrust on each ball. (b) Which ball will sink ? Give reason for your answer. ( Density of iron = 8.0 g cm-3)

WhatsApp

Answer

(a) Mass of ball A = 12 g

Mass of ball B = 12 g

The volume of the hollow iron ball A = 15 cm3

Density of iron = 8 g cm3

The volume of the hollow iron ball B = 12/8 = 1.5 cm3

Upthrut on ball A = 15 × 1 × g = 15 gf

Upthrut on ball B = 1.5 × 1 × g = 1.5 gf

(b) Solid iron ball B will sink.

Ball B experiences an upthrust of 1.5 gf in water which is less than its weight of 12 gf. Hence ball B will sink. Ball A experiences an upthrust of 15 gf that is greater than its weight of 12 gf. Hence it will float with that much part submerged for which upthrust becomes equal to its weight of 12 gf.

 

💡 Some Related Questions

Flash Education Question and Answer Icon

A weather forecasting plastic balloon of volume 15 m3 contains hydrogen of density 0.09 kg m-3. The volume of an equipment carried by the balloon is negligible compared to it’s own volume. The mass of the empty balloon alone is 7.15 kg. The balloon is floating in air of density 1.3 kg m-3. Calculate : (i) the mass of hydrogen in the balloon, (ii) the mass of hydrogen and balloon, (iii) the total mass of hydrogen, balloon and equipment if the mass of equipment is x kg, (iv) the mass of air displaced by balloon and (v) the mass of equipment using the law of floatation.

Open Answer »
Close Menu