(a) Mass of ball A = 12 g
Mass of ball B = 12 g
The volume of the hollow iron ball A = 15 cm3
Density of iron = 8 g cm–3
The volume of the hollow iron ball B = 12/8 = 1.5 cm–3
Upthrut on ball A = 15 × 1 × g = 15 gf
Upthrut on ball B = 1.5 × 1 × g = 1.5 gf
(b) Solid iron ball B will sink.
Ball B experiences an upthrust of 1.5 gf in water which is less than its weight of 12 gf. Hence ball B will sink. Ball A experiences an upthrust of 15 gf that is greater than its weight of 12 gf. Hence it will float with that much part submerged for which upthrust becomes equal to its weight of 12 gf.