QQuestion
Ammonia burns in oxygen as shown below.
4\mathrm{NH_3} + 3\mathrm{O_2} \longrightarrow 2\mathrm{N_2} + 6\mathrm{H_2O}If 240 cc of ammonia is burnt in 300 cc of oxygen, find out the composition of the resultant gaseous mixture at room temperature.
✓Answer
According to the given equation:
For N2
4 vol. of NH3 produce 2 vol. of N2
∴ 240 cc of NH3 will produce = \rac{2 \imes 240}{4} = 120 \mathrm{cc of N_2}
For O2
4 vol. of NH3 reacts with 3 vol. of O2
∴ 240 cc of NH3 will react with = \rac{3 \times 240}{4} = 180 \mathrm{cc of O_2}
Amount of unused Oxygen = 300 cc – 180 cc = 120 cc
Hence, composition of the resultant gaseous mixture at room temperature is 120 cc of O2 + 120 cc of N2.
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