The reaction between concentrated sulphuric acid and magnesium can be represented by the equation given below:
Mg + 2H2SO4 ⟶ MgSO4 + 2H2O + SO2
If 60 g of magnesium is used in the reaction, calculate:
(a) mass of acid required.
(b) volume of SO2 at STP. [Atomic weights: Mg = 24, H = 1, S = 32, O = 16]
Mg + 2H2SO4 ⟶ MgSO4 + 2H2O + SO2
(a) 24 g of Mg reacts with 196 g of H2SO4.
60 g of Mg reacts with = 196\over24 × 60 = 490 g of H2SO4.
Hence, mass of acid required = 490 g.
(b) 24 g of Mg gives 22.4 L of SO2 at STP.
60 g of Mg gives = 22.4\over24 = 56 L of SO2 at STP.
Hence, volume of SO2 at STP = 56 L.
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