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Question

At what angle must a light ray fall on the surface of an equilateral prism so that its angle of minimum deviation will be 20°?

OR

Calculate the time required by a ray of light to traverse a glass slab of thickness 2 mm. The refractive index of glass=1.5.

WBBSE Class X Physical Science Light – Reflection and Refraction 02 Mark 2024

Answer

Angle of the prism = 60°

Angle of minimum deviation (δ) = 20°

We know,

Angle of minimum deviation (δ) = 2i – A

or, δ = 2i – A

or, 2i = δ + A = 20° + 60° = 80°

or, i = 40°

OR

Given

  • Distance = 2 mm = 2 × 10⁻³ m
  • Speed of light in vacuum (c) = 3 × 10⁸ m/s
  • Refractive index of glass (μ) = 1.5

μ = \text{c}\over\text{v}

or, v = \text{c}\over\text{μ}

= \text{3 × 10⁸}\over\text{1.5}

= 2 × 10⁸ m/s

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