According to the following chemical equation, what volume of oxygen at S.T.P. is required for the complete combustion of 5 moles of methane?
CH₄ + 2O₂ → CO₂ + 2H₂O
(a) 224 L
(b) 448 L
(c) 44.8 L
(d) 22.4 L
Chemical Calculations
01 Mark
(a) 224 L
Explanation
CH₄ + 2O₂ → CO₂ + 2H₂O
From the balanced chemical equation,
1 mole of CH₄ requires 2 moles of O₂.
Therefore, 5 moles of CH₄ require = 5 × 2
= 10 moles of O₂
At S.T.P., 1 mole of any gas occupies 22.4 L.
Volume of 10 moles of O₂ = 10 × 22.4 = 224 L
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