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Question

What will be the volume of 8 g of H₂ gas (H = 1) at a pressure of 4 atmospheres and a temperature of 27°C?

[R = 0.082 litre atmosphere mole⁻¹ K⁻¹]

WBBSE Class X Physical Science 02 Mark 2025

Answer

Mass of H₂ = 8 g

Pressure (P) = 4 atm

Temperature (T) = 27°C = 300 K

Gas Constant (R) = 0.082 L atm mol⁻¹ K⁻¹

Volume (V) = ?

Molar mass of H₂ = 2 g/mol

Number of moles (n) = \frac{\text{Mass}}{\text{Molar Mass}}

= \frac{8}{2}

= 4 mol

Ideal Gas Equation : PV=nRT

Volume (V) = \frac{\text{nRT}}{\text{P}}

= \frac{4 × 0.082 × 300}{4}

= 24.6 L

Hence, the volume of 8 g of H₂ gas is 24.6 L

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